(6x^2+17x+7)/(3x+4)

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Solution for (6x^2+17x+7)/(3x+4) equation: 


D( x )

3*x+4 = 0

3*x+4 = 0

3*x+4 = 0

3*x+4 = 0 // - 4

3*x = -4 // : 3

x = -4/3

x in (-oo:-4/3) U (-4/3:+oo)

(6*x^2+17*x+7)/(3*x+4) = 0

6*x^2+17*x+7 = 0

6*x^2+17*x+7 = 0

DELTA = 17^2-(4*6*7)

DELTA = 121

DELTA > 0

x = (121^(1/2)-17)/(2*6) or x = (-121^(1/2)-17)/(2*6)

x = -1/2 or x = -7/3

(x+7/3)*(x+1/2) = 0

((x+7/3)*(x+1/2))/(3*x+4) = 0

( x+1/2 )

x+1/2 = 0 // - 1/2

x = -1/2

( x+7/3 )

x+7/3 = 0 // - 7/3

x = -7/3

x in { -1/2, -7/3 }

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